A sample of gas occupies 1.50 litre at 25°c if the temperature is raised 60°c what is the new volume of gas at constant pressure.

solution

expalnation by charles law

v1/t1=v2/t2

where,

$V_1\text{ and }T_1$ are the initial volume and temperature of the gas.

$V_2\text{ and }T_2$ are the final volume and temperature of the gas.

given we have

v1=1.50liter

t1=25degree celcius =(25+273)k=298k

v2=?

t2=60degree celcius=(60+273)k=333k

Putting values in above equation, we get:

1.50 liter / 298k = v2 / 333

we have,

v2=1.68liter

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